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Now showing items 11-20 of 27

#### MathsCasts: Cramer's Rule for 3 Unknowns

(Swinburne Commons, 2011)

This screencast first gives the general form of Cramer's Rule for solving three equations in three unknowns and then covers a specific example to demonstrate the rule.

#### MathsCasts: Truth Tables

(Swinburne Commons, 2011)

A demonstration of how to set up a truth table for a Boolean expression, in the context of a particular example.

#### MathsCasts: Partial Fractions: Example 3

(Swinburne Commons, 2012)

An example of calculating partial fractions when one of the factors on the denominator is an irreducible quadratic factor.

#### MathsCasts: What's Wrong? Cancellation of Algebraic Fractions

(Swinburne Commons, 2013)

We look at an example of a case where an algebraic fraction is actually already in its simplest form, and some of the common errors people make in trying to 'cancel' terms in this case.

#### MathsCasts: Composite Hyperbolic Functions Involving an Inverse Function: Example 2

(Swinburne Commons, 2016)

In this recording we look at a second example of how to write a composite hyperbolic function as an algebraic function of x.

#### MathsCasts: Differentiation by First Principles Example: Quadratic Function

(Swinburne Commons, 2016)

Example of using differentiation by first principles to evaluate the derivative of a quadratic function.

#### MathsCasts: Gaussian Elimination: Infinite Number of Solutions

(Swinburne Commons, 2011)

An example that works through the process of Gaussian elimination for a system with three equations in three unknowns where there are an infinite number of solutions and the final answer is hence written in terms of a parameter t.

#### MathsCasts: Cramer's Rule for 2 Variables

(Swinburne Commons, 2011)

This screencast first gives the general form of Cramer's Rule for solving two equations in two unknowns and then covers a specific example to demonstrate the rule.

#### MathsCasts: Karnaugh Maps with 4 Variables

(Swinburne Commons, 2011)

Example of simplifying a Boolean expression by using a 4-variable Karnaugh map.

#### MathsCasts: Karnaugh Maps SOP and POS

(Swinburne Commons, 2011)

With reference to a specific example, this screencast demonstrates how to use a 4-variable Karnaugh map and De Morgan's laws to simplify a Boolean expression of 4 variables both into a 'sum of products' and a 'product of sums'.